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8x^2+19x-27=0
a = 8; b = 19; c = -27;
Δ = b2-4ac
Δ = 192-4·8·(-27)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-35}{2*8}=\frac{-54}{16} =-3+3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+35}{2*8}=\frac{16}{16} =1 $
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